Monday, May 19, 2008

Conics quizzes

Well, since i heard that the test for this unit is coming very soon I decided to compile a bunch of links that will help all of us to study, so without further ado here it is:

Link 1
Link 2
Link 3
Link 4
Link 5
Link 6
Link 7
Link 8

I hope that those links will be very useful to all of us on the upcoming test and especially the provincial exams which is only 20 days away. Leave a feedback if any of those links doesn't work.

-m@rk

Difference between a hyperbola and ellipse

This was a comment that I made regarding Joyce's BOB post.



Joyce,

After reading your BOB post, I can see that you are having troubles with the differences between the standard form of ellipse and hyperbola. They are very similar and sometimes hard to distinguish because Mr. K might algebraically massage them and make them look harder than they actually are. I think that there is only one difference between them. On a ellipse the terms are suppose to have the same signs. On the other hand, on the hyperbola the terms should have opposite signs. To further enhance your learning about this you can check this out: http://people.richland.edu/james/lecture/m116/conics/conics.html

Thursday, May 15, 2008

Hyperbolas

Since my AP exam is done I can now go back to my mentoring duties and probably swing by my precalculus class once in a while. This is my comment on Francis's scribe post concerning hyperbolas. Anyways this is only my 22nd post so i got to increase the frequency of my post and the quality of my work.


Francis,

I know that this comment is about a day late but they always say that its better late than never. I really like how you illustrate the step by step process of how you get the answer. It kinda shows the missing pieces of information that are not on the slides. It helps someone like me who doesn't remember a single thing from the conics section to recall everything. Thank you and job well done. Since my AP class is over , shall i say that I'll see you in class tomorrow.

-m@rk

Saturday, May 3, 2008

The secret of Pascal's Triangle

Benofschool,

Very well summarized scribe post. It really helped me refresh my memory.Anyways, for your challenge on finding the fibonacci sequence on the triangle. The fibonacci sequence can be found by getting the sum of the numbers diagonally. This is very well explained here: http://goldennumber.net/pascal.htm.
Lastly, a little spoiler for your next class is also on that site.

-m@rk

Sunday, April 27, 2008

Exponents and Logarithms worksheet

Here is another comment regarding Zeph's questions. I really enjoy answering questions. It sorts of review me about everything i learned last year.


Zeph,

Now I'm going to show you how to do question 16. Special credits to benofschool for showing me how to do this.

[log_3(X)]^2 - log_3(x)^2 = 3

Apply the rules of logarithms.

[log_3(x)]^2 - 2log_3(x) = 3

Let, log_3(x)= y

y^2-2y=3

Apply algebraic massage

y^2-2y-3=0

Solve for y.

(y+1) (y-3)=0

y=-1 y=3

Substitute back log_3(x)= y

log_3(x)=-1 and log_3(x)=3

x= 1/3 and 27

I'm going to post the answer for the other questions tomorrow.

-m@rk

Exponents and Logarithms worksheet

This was my answer regarding Zeph's question. He was asking on how to do a specific question because he was not in class for the whole week because of some extra curricular activity. Here it is.


Zeph,

I'm going to answer your second question first, since it is tougher.

Question 15

logX^2 = (logX)^2

First is to apply the rules for logarithms.The equation will look like this:

2logX= (logX)^2

Now, let logX= y (or some other variable. The equation will look like this:

2y=y^2

Do some algebraic massage

0=2y-y^2

0= y (2-y)

y= 0 and y=2

Now substitute back logX=y

logX=0 and logX=2

Take antilog of both sides

x=10^0 and x=10^2

x=1 and x=100

-m@rk

Thursday, April 24, 2008

BOB Version 4: Exponents and Logarithms

This was my comment on Zeph's BOB post. I've finally caught up on my mentoring duties. Again, I apologize, If I'm doing my comments a little late, It is just because that AP exams are just around the corner and its almost crunch time.

Zeph,

Good BOB post! It seems to me that this new format is going to attract more attention. There are more people who are going to imitate this, much like your other format. Over my two years with Mr. K, I've never seen this done before. You are continually proving that math coexist with language. Good luck on the upcoming test.

-m@rk